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| | #1 |
| Junior Member Join Date: Jul 2009
Posts: 2
| General Question about impedence im looking into building a 1x15 bass cab to go along with my 2x10 and Ampeg SVT3, im leaning toward the TL606 i think its called. My problem is that my 2x10 has a 4 ohm impedence, which means hooking up another 4 ohm, or even 8 ohm is going to leave the impedence at 2 or 2.66 which are both going to ruin my amplifier. even if i get the second cabinet at 16 ohms, the two together will make 3.4 or something like that which is still too low. My question: is there some way i can hook the speakers up in a different way to make a minimum of 4 ohms total with the three speakers? I might consider taking the bottom off my 2x10 and fuzing it with the 1x15 that i'll build inorder to make one "cabinet" instead of having two. Thanks a lot, if this has been answered, a link to the thread would be awesome |
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| | #2 |
| Old Timer Join Date: May 2007 Location: pacific north west
Posts: 1,483
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Open up your 2X10 and rewire it for 16 ohms (assuming it's two 8 ohm speakers). Or better yet, wire up a 4/16 ohm switch and mount it on the cabinet. Then build your 1X15 at 8 ohms for a total ohm load of 5.3 with both cabs plugged in. This way you can still use either cab seperately too. Or build a crossover so you can build the 1X15 at 4 ohms and leave the 2X10 at 4 ohms. You will maximize watts this way and improve speaker performance. Chuck |
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| | #3 |
| Senior Member Join Date: Mar 2007 Location: Philadelphia suburbs
Posts: 366
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I agree with Chuck. Also, don't open up the 2 x 10 and fuse it with the 1 x 15 to make one cabinet. Each driver(s) will be happier in their own enclosure with like speakers (i.e., the 2 x 10 is fine). The box volume and porting parameters of the 10's and 15 are not likely to be similar, therefore they require different enclosures for the best performance.
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| | #4 | |
| Junior Member Join Date: Jul 2009
Posts: 2
| Quote:
Awesome responce Chuck thanks a lot | |
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| | #5 |
| Old Timer Join Date: May 2007 Location: pacific north west
Posts: 1,483
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Cool. Glad I could help. There are some other considerations... With the 2x10 at 16 ohms and the 15 at 8 ohms you will be putting most of your watts into the 15. If this seems OK then there's no other problem with this arrangement. If you really want to hear the 10's balanced with the 15 you have four options I can think of. 1) buy two more 10's at 4 or 16 ohms and wire the 2x10 for 8 ohms. 2) build a crossover and use a 4 ohm 15, as mentioned earlier. 3) buy another complete 2X10 cabinet, wire it for 16 ohms also and run it parallel to the other 2X10 cabinet with a Y splitter. So you'd have 1X15 and 4X10's 4) use a 16 ohm 15 for a total ohm load of 8. This won't give you as many watts as a 4 ohm (or 5.3 ohm) load though. Just FYI Chuck |
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| | #6 |
| Supporting Member Join Date: Apr 2009 Location: NY, NY
Posts: 215
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Chuck, would you mind explaining to me or pointing me to place that explains how a crossover is built? pete |
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| | #7 | |
| Old Timer Join Date: May 2007 Location: pacific north west
Posts: 1,483
| Quote:
No offence intended, but this is definitely one of those subjects that can be be found with a few Google searches. I know because I have done it myself. Asking me to spoon feed the info to you assumes that your time is more valuable than mine. I couldn't possibly remember all (or any of) the sites I've seen on the subject. Many relate to car audio, but who cares. Watts are watts. A crossover is simply a device that employs inductors and capacitors to direct certain frequencies to certain speakers. The fact that you post here is indicative that you could probably figure it out from there. Good search text would be: "crossover design" (in quotes as shown) crossover inductor capacitor crossover schematic (both with and without quotes) crossover calculator (this is a good one once you've learned some basics) Good luck and have fun. Chuck | |
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| | #8 |
| Supporting Member Join Date: Apr 2009 Location: NY, NY
Posts: 215
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You're right Chuck, I should have just looked it up on my own first, before posting that question. Sorry to have bother you. Regards pete |
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