Fala velhinho. By just looking(not familiar with the circuit) that circuit will sum the rectified voltages passing through the resonant pair in the coil + capacitor test circuit. The JFET will buffer your input and pass through a signal with similar amplitude to that the LC filter let pass. The band pass energy is then accumulated (rectified + stored in capacitors).
You probably then divide the input voltage / accumulated output voltage to find the Q. The more precise the LC pair is, the smaller band of voltages it'll let acumulate in c6 and c7.
My OCD complains that he wrongly calls JAF1's inductance impedance
It would be possible to describe everything scientifically, but it would make no sense; it would be without meaning, as if you described a Beethoven symphony as a variation of wave pressure. — Albert Einstein
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