I decided to use cathode bias power amp using either 6V6 or 6L6. This is my calculation. Please advice:
1) For 6V6 at 400V between plate and cathode and assuming cathode to grid is 35V. For 10W per tube, idle current is 10W/400V=25mA per tube. So for two tubes is 50mA. The cathode resistor is 35V/0.05A=700ohm.
2) For 6L6 at 400V. Assuming cathode to grid is 45V. For 20W, idle current is 20W/400V=50mA. So the pair use 100mA. Resistor is 45V/0.1A=500ohm.
Thanks
1) For 6V6 at 400V between plate and cathode and assuming cathode to grid is 35V. For 10W per tube, idle current is 10W/400V=25mA per tube. So for two tubes is 50mA. The cathode resistor is 35V/0.05A=700ohm.
2) For 6L6 at 400V. Assuming cathode to grid is 45V. For 20W, idle current is 20W/400V=50mA. So the pair use 100mA. Resistor is 45V/0.1A=500ohm.
Thanks
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