My explanation of the tremolo circuit:
The input tube V2 is wired as an inverting amp with voltage feedback from plate to grid. The first V1 is the LFO that drives the grids of second V1, which act(s) as a variable/controlled resistance which in turn modulates the gain/feedback of the input tube V2 by variable voltage dividing.
The 69 wiring of the 2 triodes of the second V1 makes sense as there is no DC current. When the plate signal of V2 goes positive, only the right side triode of the pair conducts while the left triode is blocked. When signal polarity reverses the left triode of the pair conducts and the right one blocks. So we get a modulated "bipolar" impedance.
The input tube V2 is wired as an inverting amp with voltage feedback from plate to grid. The first V1 is the LFO that drives the grids of second V1, which act(s) as a variable/controlled resistance which in turn modulates the gain/feedback of the input tube V2 by variable voltage dividing.
The 69 wiring of the 2 triodes of the second V1 makes sense as there is no DC current. When the plate signal of V2 goes positive, only the right side triode of the pair conducts while the left triode is blocked. When signal polarity reverses the left triode of the pair conducts and the right one blocks. So we get a modulated "bipolar" impedance.
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