I've got a SWR Mo' Bass on the bench which blew up, taking out both output channels and the preamp too. I replaced one of the output modules and reworked the other one, but they both have the +75V rail shorting to the output. They use the same output circuit as the SM-900 in this amp. All the semiconductors and resistors measure OK with my DMM. Capacitor C7 smoked because there was 150V across it. I've got the preamp pulled.
If I pull the AC Terminal input to the output module, the rail short goes away.
If I short R34, thereby shutting off Q14, the rail short also goes away.
What is the purpose of that AC input circuit?
I'm thinking that the collector of Q14 should sit around 2 diode drops above ground, not at the positive rail.
The power supply filter caps get their ground through the preamp PCB, It makes the amp real fun to work on until you figure that out.
Any ideas?
Thanks in advance.
If I pull the AC Terminal input to the output module, the rail short goes away.
If I short R34, thereby shutting off Q14, the rail short also goes away.
What is the purpose of that AC input circuit?
I'm thinking that the collector of Q14 should sit around 2 diode drops above ground, not at the positive rail.
The power supply filter caps get their ground through the preamp PCB, It makes the amp real fun to work on until you figure that out.
Any ideas?
Thanks in advance.
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