I'm trying to determine the output impedance of my Lifco Cobra Mark II amp head. I'm using this guide Output Transformers and Impedance and a few others and since I'm very new to this I just want someone to help me confirm that I'm doing it correctly and not missing something.
I'm connecting a 12v AC wall wart to the tube side of the output transformer (the smaller one near the output tubes). I've removed the tubes (not sure if I have to) and connected the 12 volts with aligator clips to the pins of the tube that lead to the transformer. My volt meter gives me a measurement of 0.2 volts at the output jack. Which leads directly from the transformer.
12 divided by .2 gives me 60. so the turn ratio is 60:1.
60x60=3600
3600 x 2 ohm load would give me 7200 which is probably correct for this amp with 2 6V6 power tubes.
So does that seem right? Am I missing something? One thing I am wondering is should I have disconnected the leads of the transformer from the circuit before I do this?
I have been running this amp with a 16 ohm cabinet. :O
Thanks very much for any input.
I'm connecting a 12v AC wall wart to the tube side of the output transformer (the smaller one near the output tubes). I've removed the tubes (not sure if I have to) and connected the 12 volts with aligator clips to the pins of the tube that lead to the transformer. My volt meter gives me a measurement of 0.2 volts at the output jack. Which leads directly from the transformer.
12 divided by .2 gives me 60. so the turn ratio is 60:1.
60x60=3600
3600 x 2 ohm load would give me 7200 which is probably correct for this amp with 2 6V6 power tubes.
So does that seem right? Am I missing something? One thing I am wondering is should I have disconnected the leads of the transformer from the circuit before I do this?
I have been running this amp with a 16 ohm cabinet. :O
Thanks very much for any input.
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