I was talking about the supply rails for the amplifier/output section- not the +&-15V. Marked V+ and V- on the schematic.
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Originally posted by The Dude View PostI was talking about the supply rails for the amplifier/output section- not the +&-15V. Marked V+ and V- on the schematic.
Thanks,
nosajsoldering stuff that's broken, breaking stuff that works, Yeah!
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What matters is that they are both present, both roughly the same voltage, and both clean. it matters not whether it is 49v or 52v.
Considering the 80v filter caps, I;d say 50v sounds reasonable. On most any amp, you can figure from its rated output what the peak voltage out would be, then add maybe 5v to that for roughly what the rail V will be. Very rare that it would be wrong, more likely it will be missing, or loaded WAY down, or reading low due to loss of filtration, But a smooth DC at say 30v on one side and 50v on the other is unlikely. Of if you get 50v not to worry that they intended 45v.Education is what you're left with after you have forgotten what you have learned.
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Originally posted by Enzo View PostWhat matters is that they are both present, both roughly the same voltage, and both clean. it matters not whether it is 49v or 52v.
Considering the 80v filter caps, I;d say 50v sounds reasonable. On most any amp, you can figure from its rated output what the peak voltage out would be, then add maybe 5v to that for roughly what the rail V will be. Very rare that it would be wrong, more likely it will be missing, or loaded WAY down, or reading low due to loss of filtration, But a smooth DC at say 30v on one side and 50v on the other is unlikely. Of if you get 50v not to worry that they intended 45v.
Or am I going the wrong way?
Thanks, nosajsoldering stuff that's broken, breaking stuff that works, Yeah!
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My theory is that, although you have signal at the output, it is lower level than it should be. Connecting a load simply lowers it to a point that you can no longer measure it. Can you measure the signal level at the output (unloaded) and tell us what it is? Is it enough to even drive a speaker?"I took a photo of my ohm meter... It didn't help." Enzo 8/20/22
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Originally posted by The Dude View PostMy theory is that, although you have signal at the output, it is lower level than it should be. Connecting a load simply lowers it to a point that you can no longer measure it. Can you measure the signal level at the output (unloaded) and tell us what it is? Is it enough to even drive a speaker?soldering stuff that's broken, breaking stuff that works, Yeah!
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OK, then you have *voltage* at speaker out but no *current* capability, thatīs why you canīt drive a speaker.
That means the "voltage generator driving the load" which is the Power Amp has high internal impedance so voltage drops tremendously when loaded.
You might have:
* healthy amplifier but something open in the output path: broken track/solder/connector , so a weak signal still jumps the break, enough to drive a meter (1 to 10M input impedance) but fails miserably driving 8 ohms.
By the way, I suspect those 10V do not drop down to absolute *zero* but maybe a few mV, check that.
* open emitter resistors or open output transistors (so load is driven by the drivers only) or open drivers (so load is driven by the Vas stage, the voltge gain stage which drives the drivers)
Any of these woud show healthy voltge but die driving a load.
Disconnect load, drive amp to some voltage such as 10V RMS, connect load, watch voltage die at the speaker connector (what you found so far) but remeasure VAC at bthe actual speaker out rail , such as the node: D2-D1 .
Measure continuity across L1 and between node D2-D1 ; if L1 opens (or track/solder fails) R39 (10 ohms) mkay burn open and become, say, 10k or 100k or any residual value its ashes may btake.
That would certainly turn amplifier into a high impedance generator.
* there is the distinct possibility that load or cable or connector or probes are shorting the amplifier speaker outputJuan Manuel Fahey
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Originally posted by J M Fahey View PostOK, then you have *voltage* at speaker out but no *current* capability, thatīs why you canīt drive a speaker.
That means the "voltage generator driving the load" which is the Power Amp has high internal impedance so voltage drops tremendously when loaded.
You might have:
* healthy amplifier but something open in the output path: broken track/solder/connector , so a weak signal still jumps the break, enough to drive a meter (1 to 10M input impedance) but fails miserably driving 8 ohms.
By the way, I suspect those 10V do not drop down to absolute *zero* but maybe a few mV, check that.
* open emitter resistors or open output transistors (so load is driven by the drivers only) or open drivers (so load is driven by the Vas stage, the voltge gain stage which drives the drivers)
Any of these woud show healthy voltge but die driving a load.
Disconnect load, drive amp to some voltage such as 10V RMS, connect load, watch voltage die at the speaker connector (what you found so far) but remeasure VAC at bthe actual speaker out rail , such as the node: D2-D1 .
Measure continuity across L1 and between node D2-D1 ; if L1 opens (or track/solder fails) R39 (10 ohms) mkay burn open and become, say, 10k or 100k or any residual value its ashes may btake.
That would certainly turn amplifier into a high impedance generator.
* there is the distinct possibility that load or cable or connector or probes are shorting the amplifier speaker output
Thanks so much guys
nosajsoldering stuff that's broken, breaking stuff that works, Yeah!
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Originally posted by J M Fahey View PostOh, they DO break somewhat often.
Just run a bead of silicone sealant fixing it to the PCB
Hot glue is not good enough because itīs rigid and sometimes cracks.
Juan thank you so much for the detail in why things break in the way that they do I like it so much better that here change this partand be done with it.
Thanks,
nosajsoldering stuff that's broken, breaking stuff that works, Yeah!
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