Very nice work, Mel!
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Distortion Booster in Thomas Vox V1032?
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Originally posted by johnnysavant View PostOK, silly but simple question here. I just picked up a V1032 Cambridge. I only collect Vox tube amps, so I don't know a whole lot about the Thomas solid state amps. This V1032 amp is missing the pilot light bulb.
What light bulb # goes in the V1032?
See if that looks like it is the correct one.
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Originally posted by 52 Bill View PostMy parts list has the pilot lamp as a #1892 lamp.
See if that looks like it is the correct one.
Thanx again.
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Without a working bulb, there will be no voltage drop across the resistor. If your lamp draws 100ma, 10v will drop across that 100 ohm resistor.
Got another 100 ohm resistor? Clip it across the bulb socket, now see if you don;t have about 12v on the socket.
Ohm's Law.Education is what you're left with after you have forgotten what you have learned.
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Originally posted by olddawg View PostHow times have changed... back in the day when I was young you could pick up a complete, working Super Beatle and cab with frame for $50-$75 because nobody wanted one. We would pull the speakers out to make monitor wedges and toss the rest in the dumpster!
Supply and demand babyJuan Manuel Fahey
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Originally posted by Enzo View PostWithout a working bulb, there will be no voltage drop across the resistor. If your lamp draws 100ma, 10v will drop across that 100 ohm resistor.
Got another 100 ohm resistor? Clip it across the bulb socket, now see if you don;t have about 12v on the socket.
Ohm's Law.
Thx
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I added the second resistor only as a substitute for the bulb. To demonstrate that a load (bulb or resistor) will cause that voltage to fall into place. I was not suggesting adding more resistance to the circuit as a modification.Education is what you're left with after you have forgotten what you have learned.
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Originally posted by Enzo View PostI added the second resistor only as a substitute for the bulb. To demonstrate that a load (bulb or resistor) will cause that voltage to fall into place. I was not suggesting adding more resistance to the circuit as a modification.
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