I don't think in terms of more negative or positive, though that would be the case. I think of the bias as maintaining a voltage space between those opposing driver bases. That is what prevents crossover. Instead of the bases sitting at zero volts, each sits a bit above and below zero. We want the DC levels to be just where the transistors start to turn on. If a transistor base starts at zero, then the signal has to rise up to about a half a volt befiore that transistor turns on. So a little half volt bite comes out of the signal. But bias the base up to half a volt, and now the signal can start amplifying at the first instant, no little crossover bite. That covers the driver, but add in the output transistor, that adds another half volt. So two half volts up and two half volts down, that means Q4 would needd set a 2 volt difference across itself. (I am not looking at the schematic, so if there are additional transistors, we adjust for them.)
Left on its own, Q4 would center around zero. Whatever voltage we put on it, the output follows. it just maintains that 2 volt space wherever we push it. That is how we send signal through it. Q3 tugs it up and down, through your R11. Signal moves Q4 up and down, and the outputs follow.
To do that we need current flowing through Q3, so there is a circuit strip from V+ down through Q10, R5, R9, Q4, R11, Q3, R32, to V-. Q10 is more or less a switch, the mute circuit turns it on to energize the front half of the power amp. SO normally Q3 turns on enough to pull Q4 to center. Now signal from Q1 will turn Q3 on more and less to increase and decrease current through Q3, which has the effect of moving Q4 up and down in voltage.
So shorting Q4 just means all that happens without leaving the 2 volt space. And that means as your signal crosses zero it has go go that extra volt each way before the outputs conduct current to the speaker.
Left on its own, Q4 would center around zero. Whatever voltage we put on it, the output follows. it just maintains that 2 volt space wherever we push it. That is how we send signal through it. Q3 tugs it up and down, through your R11. Signal moves Q4 up and down, and the outputs follow.
To do that we need current flowing through Q3, so there is a circuit strip from V+ down through Q10, R5, R9, Q4, R11, Q3, R32, to V-. Q10 is more or less a switch, the mute circuit turns it on to energize the front half of the power amp. SO normally Q3 turns on enough to pull Q4 to center. Now signal from Q1 will turn Q3 on more and less to increase and decrease current through Q3, which has the effect of moving Q4 up and down in voltage.
So shorting Q4 just means all that happens without leaving the 2 volt space. And that means as your signal crosses zero it has go go that extra volt each way before the outputs conduct current to the speaker.
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