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calculating output power

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  • calculating output power

    I am trying to calculate the output power of a Sunn bass amp. I've got two 6550s into an 8 ohm dummy load. I can get just about 30v peak at 1khz before the signal clips. With the formula I found I came up with about 56 watts rms. Does that sound right?
    David

  • #2
    Sounds about right.
    Education is what you're left with after you have forgotten what you have learned.

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    • #3
      Thanks Enzo,

      looks like I might have got at least one thing right this weekend, now if I can just catch this stupid mouse in my basement that apparently doesn't like peanut butter.
      David

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      • #4
        Originally posted by dwhutchens View Post
        looks like I might have got at least one thing right this weekend, now if I can just catch this stupid mouse in my basement that apparently doesn't like peanut butter.
        David
        Was that 30v as measured in your O'scope or with a "rms" reading AC voltmeter?
        Bruce

        Mission Amps
        Denver, CO. 80022
        www.missionamps.com
        303-955-2412

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        • #5
          That was 30v peak or 60v p-p measured on my oscope.
          David

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          • #6
            Then your reading is as accurate as the scope display plus your ability to interpret it. As a ball park estimate, it should be close.
            Education is what you're left with after you have forgotten what you have learned.

            Comment


            • #7
              So should I be using the scope to determine when clipping starts and an rms meter to measure the voltage drop on the dummy load to get the most accurate reading? I have an old fluke bench meter, I'm not sure if its rms or not. I'm not in front of it right now and I don't remember the model number.
              Thanks,
              David

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              • #8
                I find reading it from the scope is close enough for R'nR.

                P (watts rms) = V p to p divided by 2 multiplied by
                .707 (to convert to R.M.S.)
                square it then divide by the load in ohms
                so 50volts p to p becomes 25 x.707 = 17.675
                17.675 squared = 312.40562525
                divided by 8 (ohms) =39.050703125 watts rms

                so 30 volts peak x .707 = 21.21 volts rms
                21.21 squared = 449.8641
                449.8641 divided by 8 (0hms) =56.2330125

                'cuse the scrawl

                mind you those 200watt 20 buck plastic computer speakers look good value..!

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                • #9
                  Even if your meter is not "RMS" it will still be close. Use a sine wave test signal.
                  Education is what you're left with after you have forgotten what you have learned.

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                  • #10
                    Yea, I was using a function generator set for a 1khz 100mv sine wave.
                    David

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