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Mesa GEQ Inductors - Gyrators
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I'm not sure you have the right form of gyrator. Doesn't the Mesa circuit have slide pots with series LC tanks to ground? Why does your circuit have In's and Out's? The circuits I've seen simulated the inductor to ground and the cap blocked DC so a split supply wasn't required. You just need to make sure the gyrators don't run out of current and that depends on how much signal the equalizer needs to handle.WARNING! Musical Instrument amplifiers contain lethal voltages and can retain them even when unplugged. Refer service to qualified personnel.
REMEMBER: Everybody knows that smokin' ain't allowed in school !
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The nodes you have labelled as "out" are not outputs. They should connect to reference voltage, equal to approximately half of the total power supply voltage. In dual supply circuits you can simply connect them to ground but if you use a single-rail supply and ground the emitters the nodes must connect to Vcc/2, most conveniently made by a resistive divider with the bottom resistor AC bypassed. Fortunately all gyrators can likely use the same DC reference to simplify the circuit.
As far as I know, these kinds of gyrator circuits need to have one end grounded. Since the circuit in the EQ is a series resonance circuit it's easy to arrange simply by changing the order of the components in the series string. For example, place the capacitors (connecting to ground in your schematic) before the gyrator inductors. The gyrators will ground the strings.Last edited by teemuk; 10-13-2009, 07:24 AM.
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Originally posted by teemuk View PostAs far as I know, these kinds of gyrator circuits need to have one end grounded.
Look at RG Keen's EQ article to see how it all wires up."Enzo, I see that you replied parasitic oscillations. Is that a hypothesis? Or is that your amazing metal band I should check out?"
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Teemu might know better, but I think the 100R resistor will be OK as long as it's large compared to the transistor's internal emitter resistance. That's (26/Ic) ohms, or whatever. If it's not, you either need a bigger resistor, or more collector current.
You can make the same circuit with an op-amp follower instead of the transistor, it's easier to design because the op-amp is closer to an ideal follower. It may even take up less board space if you use quad op-amps."Enzo, I see that you replied parasitic oscillations. Is that a hypothesis? Or is that your amazing metal band I should check out?"
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I know that its easier to design with op-amps but I don't like them, I want to make discrete gyrators.Can I put 1K's instead of 100R's and decrease 100nF's to the 10nF's, or out resistors (100K, 39K, 22K to 10K, 3.9K, 2.2K...)? The value of inductance will not change.
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The inductance won't change, but the Q will decrease because of the added series resistance. That's probably why that point is called the Q point. The result will be that you'll get less dBs of boost/cut than if you'd used 100R.
I find a simulator like LTSpice very useful for simulating EQ circuits like this."Enzo, I see that you replied parasitic oscillations. Is that a hypothesis? Or is that your amazing metal band I should check out?"
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I'll try to replace mesa inductors with gyrators, but I need some help
I have a PCB image if you're interested. It was designed for 30mm travel slide pots to be soldered directly to the board but can be used with other pots as well.
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I searched the schematics of different GEQ's and I found that typical value for Q-point resistor is 330R, 470R on Op-amp based gyrators and 1K transistor based gyrator on DOD FX-40B. I found 100R on Rod Elliot's example of gyrator,so maybe he was just using it for easier calculations as a example.
What will change If
1.R1-Q-point-1K, R2-10K, C1-100nF?
2.R1-Q-point-1K, R2-100K, C1-10nF?
Inductance and frequency wont, but what will happen with signal,does it mean that gain will be smaller with 100K,because of larger series resistance?
Thanks guys.
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I searched the schematics of different GEQ's and I found that typical value for Q-point resistor is 330R, 470R on Op-amp based gyrators and 1K transistor based gyrator on DOD FX-40B. I found 100R on Rod Elliot's example of gyrator,so maybe he was just using it for easier calculations as a example.
What will change If
1.R1-Q-point-1K, R2-10K, C1-100nF?
2.R1-Q-point-1K, R2-100K, C1-10nF?
Inductance and frequency wont, but what will happen with signal,does it mean that gain will be smaller with 100K,because of larger series resistance?
Thanks guys.
Guitar Pedals: Gyrator Filter Calculator
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