Originally posted by brodude
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Originally posted by brodude
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Originally posted by brodude
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The power rating of the resistor should be about double what the resistor actually sees. eg. if it is a 470R resistor and it sees 30V at the cathode, then the power burned up in it is: (30V/470R) x 30V = 1.91W (say 2W) therefore the cathode resistor would need to be about 5W to be safe. If you have two resistors in series then the total power dissipated across them with be shared between them proportionately according to their relative resistances.
Originally posted by brodude
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