Originally posted by defaced
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It's really simple. Load impedance across a B+ voltage determines output power (Power = Voltage^2 / Load). Peak-peak voltage swing across the plate-plate load = double the B+, and Peak-Peak Voltage^2 / Plate-Plate Load Impedance = Peak Power. 1/2 peak power = average power.
Tubes just control the current flow through said load.
If you draw up a simple 2 resistor voltage divider, but make the grounded resistor a pot, the pot would represent the tube. Rotation of the pot represents input signal. The top fixed resistor represents 1/2 the OT primary.
As you rotate the pot one way, resistance drops, which allows more current to flow. But since the pot's resistance is dropping, so is the voltage drop across it.
At the point where the pot is at the resistance where 1/2 the peak current is being drawn and voltage across the pot is at 1/2 the max resistance voltage, it is at this current/voltage that the pot is dissipating the most power. This represents the output signal being at 1/2 the swing.
Now as you increase branch current, current through the fixed resistance also increases, which increases the voltage drop across the fixed resistance.
Once the pot reaches zero resistance, the fixed resistor is dissipating the full power and you are at peak swing.
Reverse the pot rotating for the negative swing.
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