I have two Supro 1690T amps, one a 57 and one a 61. They're almost identical although the OT are slightly different. Here's the thing: they use two 10" 8 ohm speakers in parallel for 4 ohms. All fine and dandy. When I measure the OT impedance (disconnected) I use a 9V wall power supply. Under load, it's putting out 7.58 VAC. I apply this voltage to the speaker side and get 590VAC on the tube side. This means a turns ratio of 77.8 to 1. So, the impedance ratio works out to about 6K to 1. So these two 6L6 tubes (cathode bias, about 390 plate voltage) are seeing 24K? What the heck is THAT about? Can someone expound upon why Valco would have done this, and what sonic effect this might be having as opposed to a more "typical" 4.5 to 6.6K? I thought the first one was a fluke but since I was converting to a 12" speaker and a much bigger OT anyway, I didn't care. But this second one I just picked up is the same as the first!
Am I doing the math wrong somewhere?
Am I doing the math wrong somewhere?
Comment