Hello, I'm new here and relatively new to tube electronics. I read everything I can get my hands on, books and online info. For some reason weird I love the theory part more than the practical part... and the 'electrons path of travel' thread is great, in spite of the sparks. How can you avoid sparks when we're talking about electricity
I have my own questions, related to electrons flow. I hope I'm not asking too much...
I'm reading Navy module 6, where it talks about cathode biasing. I understand what cathode biasing does, what throws me off is what the module says about the bias capacitor here RF Cafe - Navy Electricity and Electronics Training Series (NEETS), Module 6
Figure 1.23.(A) is pretty obvious. For 1.23.(B) it says that "In view B, the positive-going signal is applied to the grid. This causes increased conduction through the tube, which attempts to drive the cathode to +20 volts. But notice that the top of Ck is still at +10 volts (remember capacitors oppose a change in voltage). The top plate of Ck is, in effect, 10 volts negative in relation to the top of Rk." So far, so good...
Now comes the part I don't really get "The only way that Ck can follow the signal on the top of Rk (+20 volts) is to charge through the tube back to the source, from the source to the lower plate of Ck. When Ck charges through the tube, it acts as the source of current for the cathode. This causes the cathode to remain at +10 volts while the capacitor is charging."
So...why does Ck act "as the source of current for the cathode"? The top of Ck is at +10V, while the top of R is at +20V. Isn't the top of Rk the source of current for the cathode?
Next question... Figure 1.23.(C) says "Under these conditions", which I guess it means in response to what happened in figure (B), "conduction through Rk will decrease". Why is that? Thank you.
I have my own questions, related to electrons flow. I hope I'm not asking too much...
I'm reading Navy module 6, where it talks about cathode biasing. I understand what cathode biasing does, what throws me off is what the module says about the bias capacitor here RF Cafe - Navy Electricity and Electronics Training Series (NEETS), Module 6
Figure 1.23.(A) is pretty obvious. For 1.23.(B) it says that "In view B, the positive-going signal is applied to the grid. This causes increased conduction through the tube, which attempts to drive the cathode to +20 volts. But notice that the top of Ck is still at +10 volts (remember capacitors oppose a change in voltage). The top plate of Ck is, in effect, 10 volts negative in relation to the top of Rk." So far, so good...
Now comes the part I don't really get "The only way that Ck can follow the signal on the top of Rk (+20 volts) is to charge through the tube back to the source, from the source to the lower plate of Ck. When Ck charges through the tube, it acts as the source of current for the cathode. This causes the cathode to remain at +10 volts while the capacitor is charging."
So...why does Ck act "as the source of current for the cathode"? The top of Ck is at +10V, while the top of R is at +20V. Isn't the top of Rk the source of current for the cathode?
Next question... Figure 1.23.(C) says "Under these conditions", which I guess it means in response to what happened in figure (B), "conduction through Rk will decrease". Why is that? Thank you.
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