I realize that the attenuation of certain frequencies between stages has an immense effect on tone. I plan to experiment a little with LED/diode bias to see what sort of sound it gives (also in part due to my irrational hatred of capacitors), but I notice that this sort of removes the option of tweaking the sound through the shelving filter formed by a partially bypassed stage.
When I look at most "high-gain" designs, they use coupling capacitors of .02uf, which provides a -3db rolloff at frequencies of around 7 to 20hz depending on grid leak/stopper values, most of the time not even being able to attenuate ANY of the signal of a low E string (or at some absurd value like 0.01db).
Is this simply because of the shelving filter attenuating/not boosting the low frequencies, so essentially all the coupling capacitors do is... couple? So in a diode biased design would it be wise to reduce the value of the coupling capacitors to at least get some low frequency roll-off? I'm thinking if I actually employ the coupling capacitor as a tone shaping tool I can make a reasonable approximation of a shelf filter. Obviously they will sound different, and I don't mind that (I'm not looking to develop any 'classic' sounds here), as long as it sounds good.
Oh and I attached a rough schematic of an example gain stage. If you notice, the capacitor between the grid and the cathode is there to make a low pass filter, in place of the miller capacitance filters usually seen. This is because the miller capacitance of the valves I'm using is only 15-20pf so it's not actually possible to roll-off audible frequencies without the additional cap. As you can see from the schematic, the grid leak/stopper are configured in a voltage divider arrangement... My question is, how exactly do you calculate the roll off frequency in this arrangement? Is the total resistance value simply the parallel of the grid stop/leak resistors ?
When I look at most "high-gain" designs, they use coupling capacitors of .02uf, which provides a -3db rolloff at frequencies of around 7 to 20hz depending on grid leak/stopper values, most of the time not even being able to attenuate ANY of the signal of a low E string (or at some absurd value like 0.01db).
Is this simply because of the shelving filter attenuating/not boosting the low frequencies, so essentially all the coupling capacitors do is... couple? So in a diode biased design would it be wise to reduce the value of the coupling capacitors to at least get some low frequency roll-off? I'm thinking if I actually employ the coupling capacitor as a tone shaping tool I can make a reasonable approximation of a shelf filter. Obviously they will sound different, and I don't mind that (I'm not looking to develop any 'classic' sounds here), as long as it sounds good.
Oh and I attached a rough schematic of an example gain stage. If you notice, the capacitor between the grid and the cathode is there to make a low pass filter, in place of the miller capacitance filters usually seen. This is because the miller capacitance of the valves I'm using is only 15-20pf so it's not actually possible to roll-off audible frequencies without the additional cap. As you can see from the schematic, the grid leak/stopper are configured in a voltage divider arrangement... My question is, how exactly do you calculate the roll off frequency in this arrangement? Is the total resistance value simply the parallel of the grid stop/leak resistors ?
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