So I am checking whether the 15" https://taweber.powweb.com/weber/15f150.htm 30W speaker I got the other day will be able to handle the power output of a '65 t-bolt circuit I am planning on building next (or whether I need to order the 50W version).
Here are my assumptions (using the voltages courtesy of Weatherford Amps schematic attached herewith)
Pout = [(3.2 x Eo)^2]/(8 x Rpp) (is this the correct starting equation?)
Where: Eo is the (assumed) plate voltage swing (assumed to be about 370 with a plate idling at 410 - is this unreasonably high?), Rpp is the plate-to-plate load resistance, 2 x cathode-biased 6L6s biased to 75mA (tube current) each, Pv-Kv = 380, OT turns ratio 625:1, speaker = 8R, B+ = 410
So:
Pout = [(32. x 370)^2]/(8 x 5,000) = 35W
Or would anyone change these assumptions/equations?
Any help/criticism much appreciated. TIA
Here are my assumptions (using the voltages courtesy of Weatherford Amps schematic attached herewith)
Pout = [(3.2 x Eo)^2]/(8 x Rpp) (is this the correct starting equation?)
Where: Eo is the (assumed) plate voltage swing (assumed to be about 370 with a plate idling at 410 - is this unreasonably high?), Rpp is the plate-to-plate load resistance, 2 x cathode-biased 6L6s biased to 75mA (tube current) each, Pv-Kv = 380, OT turns ratio 625:1, speaker = 8R, B+ = 410
So:
Pout = [(32. x 370)^2]/(8 x 5,000) = 35W
Or would anyone change these assumptions/equations?
Any help/criticism much appreciated. TIA
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