Originally posted by Gingertube
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[(mu * Ra)/(Ra + 0.5*ra)] / [(mu * Ra)/(Ra + ra)]
simplifies to:
(Ra + ra) / (Ra + 0.5*ra)
Where ra = ra when unparalled.
You will find that plugging in some typical numbers shows that paralleling can result in a nice bump in voltage gain, but nowhere near the two fold you propose....which would require a non- existent plate resistor.
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