Going further with the thread derailing, this is what WW2 soldiers in their foxholes and even concentration camp inmates used when needing an "audio diode" and Mouser was still 40 years into the future: enter the mighty razorblade_and_pencil diode
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Power pentodes as preamp tubes?
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Originally posted by Old Tele man View Post<snip>
3) Multi-grid tubes have much higher dynamic plate load values than triodes and thus present LESS loading to subsequent circuits.
-Gnobuddy
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Parallel a 100KΩ input load with a 2KΩ triode output and you get something less than 2KΩ upon the input load.
Parallel that same 100KΩ input load with a 33KΩ pentode output and you get about 25KΩ...more than 10-times LESS loading upon the input load.
It's easier to generate a voltage GAIN across a larger resistance/impedance than it is across a lower resistance/impedance, because it requires less current to create that GAIN....and the Devil said: "...yes, but it's a DRY heat!"
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Originally posted by Old Tele man View PostParallel a 100KΩ input load with a 2KΩ triode output and you get something less than 2KΩ upon the input load.
Parallel a 100k input load with a 2k triode output, and you get 98% of the signal voltage making it through the voltage divider - this is called very little loading (only 2% of the voltage is lost). The load (the subsequent stage) has very little effect on the output voltage of the preceding (triode) stage.
Originally posted by Old Tele man View PostParallel that same 100KΩ input load with a 33KΩ pentode output and you get about 25KΩ...more than 10-times LESS loading upon the input load.
Originally posted by Old Tele man View PostIt's easier to generate a voltage GAIN across a larger resistance/impedance than it is across a lower resistance/impedance, because it requires less current to create that GAIN.
-Gnobuddy
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"Following" circuits are not always amplifying tubes, quite often they're RL/RC-tone shaping circuits, which attenuate passing signals QUITE a bit, so more loss means less output to subsequent circuitry, which has to MAKE UP (and usually exceed) those losses. A good designer (employed) uses as few components as necessary because of cost....and the Devil said: "...yes, but it's a DRY heat!"
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It seems topsy turvy to describe outputs as loading inputs?My band:- http://www.youtube.com/user/RedwingBand
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Sorry, still not the best description of what´s going on.
Parallel a 100KΩ input load with a 2KΩ triode output and you get something less than 2KΩ upon the input load.
It is driving the next stage, which has a 100k grid resistor.
Also applies to passive elements, next stage might have no tube whatsoever but consist of just a 100k resistor (passive load) to ground and nothing else.
Or a capacitor or inductor or any combination which, at least at that frequency, shows 100k impedance.
Any of these is loading the triode (generator) which has 2k internal impedance so in principle it´s lightly loaded.
The 2k is not "loading" anything, it´s the generator internal impedance, and definitely is not loading itself.
Parallel that same 100KΩ input load with a 33KΩ pentode output and you get about 25KΩ...
To be more precise:
* "a load" goes from generator output to ground.
* "internal impedance" is in series with generator output.
Clearly these two concepts are very different.
more than 10-times LESS loading upon the input load.
A load loads a generator.
If you put 2 loads in parallel (such as 2 speakers in parallel) would you say one is loading the other?Last edited by J M Fahey; 10-15-2017, 05:45 PM.Juan Manuel Fahey
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Originally posted by Old Tele man View PostLoading is NOT a unilateral event, it goes BOTH directions.
Is the hill forcing the cyclist to pedal harder, or is the hard pedalling creating the inline?My band:- http://www.youtube.com/user/RedwingBand
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The control-grid of a triode is 'normally' a HIGH impedance, so it presents a HIGH-Z load to whatever is sourcing/driving it. But, as soon as that grid goes positive enough to draw current (even slightly) it promptly becomes a LOW-Z load back to what is driving it...it has loaded its source beyond what it was originally intended to do.
As investigators like to say: "...Follow the current (instead of money)..."Last edited by Old Tele man; 10-14-2017, 10:25 PM....and the Devil said: "...yes, but it's a DRY heat!"
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Originally posted by Old Tele man View PostLoading is NOT a unilateral event, it goes BOTH directions.
It is, of course, entirely up to you what you want to do about that.
Kind regards,
-Gnobuddy
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Originally posted by Old Tele man View PostThe control-grid of a triode is 'normally' a HIGH impedance, so it presents a HIGH-Z load to whatever is sourcing/driving it. But, as soon as that grid goes positive enough to draw current (even slightly) it promptly becomes a LOW-Z load back to what is driving it...it has loaded its source beyond what it was originally intended to do.
As investigators like to say: "...Follow the current (instead of money)..."
Whatever, I don’t understand how that relates to your hypothesis of ‘a source impedance loading the following input’?Last edited by pdf64; 10-14-2017, 10:46 PM.My band:- http://www.youtube.com/user/RedwingBand
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