Trying to get my head around this: (The PI design appears in RDHB4 fig 12.29C, altho' I couldn't find any explanation of the circuit there)
This is surely a case where the screen is unbypassed, so the Vg2 will be bouncing up and down in phase with the Va. BUT is it not the case (as with any pentode), that prevailing the screen current is in opposing phase to the prevailing plate current (albeit you get the 'neutralising' effect of screen compression from the lack of g2 bypassing)?
Surely the screen is still at some +ve voltage that acts as an electron particle accelerator, even when the plate current is lowered
How do the internal screen resistance (rg2) and the screen resistor (Rg2) have an effect on the phasing of the screen current?
Only I am querying this elsewhere and there seems to be diverging opinions on how it all works.
Looking forward to some debate on this.
Pete
This is surely a case where the screen is unbypassed, so the Vg2 will be bouncing up and down in phase with the Va. BUT is it not the case (as with any pentode), that prevailing the screen current is in opposing phase to the prevailing plate current (albeit you get the 'neutralising' effect of screen compression from the lack of g2 bypassing)?
Surely the screen is still at some +ve voltage that acts as an electron particle accelerator, even when the plate current is lowered
How do the internal screen resistance (rg2) and the screen resistor (Rg2) have an effect on the phasing of the screen current?
Only I am querying this elsewhere and there seems to be diverging opinions on how it all works.
Looking forward to some debate on this.
Pete
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