I'm new to amp electronics but have been learning a lot in the last few months and have a few ideas I'd like to try on my amps. They are modern voiced 50W push pull PCB based amps with solid state bridge rectifiers and I'd like to put in a power reduction/sag resistors with a switch (to go back and forth) in the power supply. I'd like to reduce B+ by 50V or more as well as reduce the response/general feel of the amp to be saggier and more vintage like. Similar to imitating the response of a tube recitifier. But also reducing the voltage in general and also reducing the wattage output of the tubes. Sort of like a half power switch.
Since the amps are PCB based, it'd be hard (and more risky for someone new at this like me) to go cutting traces or bridging off of the PCB board, I'd prefer to do this before the rectifier with the crimp wires rather than on the PCB. Trying to go between the rectifier and first cap would be much more complicated and harder to reverse.
So instead of going out of the standby switch into the rectifier, I want to go from the standby switch into the resistor and then into the PCB and rectifier. So..
------------
PT secondary > standby switch > resistor (with bypass switch) > rectifier > 1st two filter caps
instead of
PT secondary > standby switch > rectifier > 1st two filter caps
------------
There are obviously two taps coming out of the PT secondary and going into the standby switch and into the rectifier, so I'd need to do all of this twice. That'd mean two resistors, two switches etc. The resistors I want to use are 25W wirewound 50, 100 or 200 ohm. With the resistors bolted to the chassis to dissipate heat, with a small PC fan exhausting air through the top of the cabinet box.
With SPDT On/On switches rated 250V/10A, would these be overkill or good enough? I want to do all of the connections with crimp connectors (where possible) and these switches have those connections. I'd want to do the switching (which puts the highest stress on the switch) when in standby so maybe this wouldn't matter, but better to be safe than sorry. There are probably smaller switches that would work, but I find it hard to find them with the right crimp connections to wire them up.
I just wanted to run this idea by the more experienced in this area incase I've made any mistakes or there are any series flaws in this idea. And also ask a question about the rectification and use of these two switches.
This is a question I've never seen asked before in relation to sag resistors, so I guess it's a good one to ask. With both resistors bypassed, it should be 100% the same as stock? And with both resistors in the circuit it'd be reduced wattage/B+ voltage and current (under load) with the possiblility of running the amp at half power (depending on the correct ohms of the resistors)? So both switches on = 50% output wattage (within reason).
But what about if one switch was on and one switch was off? As far as I can tell both amps don't have a center tap on the B+ and if they were center tapped to ground, I'm not sure if that would affect this.
I was picturing the AC signal and then the rectified signal and one wave would be bigger than the other, which would be similar to when a power transformer puts out unequal voltage in it's secondary winding? The ripple after rectification would be a different shape with every second wave having more ripple. By the time this was filtered down by the filter caps and dropping resistors (or choke).. do you think this could be a workable setting for 75% power? Would the DC voltage end up being smoothed out eventually anyway? Or would this create extra noise or problems? Could it stress the filter caps more because the ripple would be bigger?
It could be nice if this worked I guess, for 50%/75%/100% power/sag option. These amps are both fixed bias and I realise that the bias would be altered a lot while doing this (and then when rebiasing that'd change the plate voltage again and it'd have to balance out).. but if this worked well, I'd also be thinking of doing external biasing probes and pots.
I'm new to all of this stuff but just want to make sure all bases are covered. If anyone has any ideas for what could be improved or any problems that this would cause it'd be much appreciated.
Since the amps are PCB based, it'd be hard (and more risky for someone new at this like me) to go cutting traces or bridging off of the PCB board, I'd prefer to do this before the rectifier with the crimp wires rather than on the PCB. Trying to go between the rectifier and first cap would be much more complicated and harder to reverse.
So instead of going out of the standby switch into the rectifier, I want to go from the standby switch into the resistor and then into the PCB and rectifier. So..
------------
PT secondary > standby switch > resistor (with bypass switch) > rectifier > 1st two filter caps
instead of
PT secondary > standby switch > rectifier > 1st two filter caps
------------
There are obviously two taps coming out of the PT secondary and going into the standby switch and into the rectifier, so I'd need to do all of this twice. That'd mean two resistors, two switches etc. The resistors I want to use are 25W wirewound 50, 100 or 200 ohm. With the resistors bolted to the chassis to dissipate heat, with a small PC fan exhausting air through the top of the cabinet box.
With SPDT On/On switches rated 250V/10A, would these be overkill or good enough? I want to do all of the connections with crimp connectors (where possible) and these switches have those connections. I'd want to do the switching (which puts the highest stress on the switch) when in standby so maybe this wouldn't matter, but better to be safe than sorry. There are probably smaller switches that would work, but I find it hard to find them with the right crimp connections to wire them up.
I just wanted to run this idea by the more experienced in this area incase I've made any mistakes or there are any series flaws in this idea. And also ask a question about the rectification and use of these two switches.
This is a question I've never seen asked before in relation to sag resistors, so I guess it's a good one to ask. With both resistors bypassed, it should be 100% the same as stock? And with both resistors in the circuit it'd be reduced wattage/B+ voltage and current (under load) with the possiblility of running the amp at half power (depending on the correct ohms of the resistors)? So both switches on = 50% output wattage (within reason).
But what about if one switch was on and one switch was off? As far as I can tell both amps don't have a center tap on the B+ and if they were center tapped to ground, I'm not sure if that would affect this.
I was picturing the AC signal and then the rectified signal and one wave would be bigger than the other, which would be similar to when a power transformer puts out unequal voltage in it's secondary winding? The ripple after rectification would be a different shape with every second wave having more ripple. By the time this was filtered down by the filter caps and dropping resistors (or choke).. do you think this could be a workable setting for 75% power? Would the DC voltage end up being smoothed out eventually anyway? Or would this create extra noise or problems? Could it stress the filter caps more because the ripple would be bigger?
It could be nice if this worked I guess, for 50%/75%/100% power/sag option. These amps are both fixed bias and I realise that the bias would be altered a lot while doing this (and then when rebiasing that'd change the plate voltage again and it'd have to balance out).. but if this worked well, I'd also be thinking of doing external biasing probes and pots.
I'm new to all of this stuff but just want to make sure all bases are covered. If anyone has any ideas for what could be improved or any problems that this would cause it'd be much appreciated.
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