Ad Widget

Collapse

Announcement

Collapse
No announcement yet.

Decibel Equation

Collapse
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • #31
    Originally posted by Dave H View Post
    Then you should be able to get extra credit by using loudthud's formula to get log base 2 of 0.25. Look up log10 of 0.25 then divide that by log10 of 2. What do you get?
    I have no idea.....
    I had never heard of a log table before this post...much less know how to use one.
    I have a calculator that does Log10.
    But the log tables I have seen do not (i do not think they do anyway) go below Zero.
    Using my calculator:
    Log10 (0.25) = -0.602
    Log10 (2.00) = 0.301
    If I divide those, my calculator says -2.00 +/- a bit
    But how can I verify that from a Log table.?

    If I use formula:
    2). logb(m/n) = logb(m) – logb(n) ... (from that Internet link)
    I get -1.75
    Are either of those right.?
    https://www.youtube.com/watch?v=7zquNjKjsfw
    https://www.youtube.com/watch?v=XMl-ddFbSF0
    https://www.youtube.com/watch?v=KiE-DBtWC5I
    https://www.youtube.com/watch?v=472E...0OYTnWIkoj8Sna

    Comment


    • #32
      I would not get to hung up on log tables. When I was a senior in high school I bought a "Slide Rule". Of all things. The very next year Texas Instruments came out with the TI-30 hand held scientific calculator. I bought one shortly there after and never looked back. The tables were found in the backs of math textbooks and designed so that you could estimate logarithm's as well as sine and cosines using a pencil and paper. Logarithm tables only went from 1 to 10 (producing values from 0 to 1). It was assumed you could figure out which decade (or the integer portion) of the log by inspection.

      It should be noted that while logarithm results can extend from negative infinity to positive infinity the numbers (and expressions) that logarithms can be applied to can only be positive. for the same reason that you can not have a square root of a negative number.

      #2 of your expression is correct.

      Comment


      • #33
        Originally posted by g1 View Post
        I had also assumed the base 10 to be understood.
        Having it typed out in line makes it confusing. Seeing it with the 10 lower than the word log takes away the confusion, but we can't type it out like that .
        [ATTACH=CONFIG]33579[/ATTACH]
        Yes! MS Word allows for subscript and superscript formatting- you could even assign hot keys to them. But HTML and Flash are more interested in bells and whistles than meat and potatoes.
        The Blue Guitar
        www.blueguitar.org
        Some recordings:
        https://soundcloud.com/sssteeve/sets...e-blue-guitar/
        .

        Comment


        • #34
          Originally posted by trem View Post
          I have no idea.....
          I had never heard of a log table before this post...much less know how to use one.
          I have a calculator that does Log10.
          But the log tables I have seen do not (i do not think they do anyway) go below Zero.
          Using my calculator:
          Log10 (0.25) = -0.602
          Log10 (2.00) = 0.301
          If I divide those, my calculator says -2.00 +/- a bit
          But how can I verify that from a Log table.?

          If I use formula:
          2). logb(m/n) = logb(m) – logb(n) ... (from that Internet link)
          I get -1.75
          Are either of those right.?
          -2 is correct

          Sorry for suggesting log tables, my age is showing A calculator is better. The formula in 2). is not the one to use for this. You need to use loudthud's as you did to get -2 above. Formula 2). is for logs with the same base (b).

          Comment


          • #35
            Oops... My bad... Shot my mouth off again. Dave H is correct. (shows red face)http://music-electronics-forum.com/i...ies/tongue.png

            Should be able to do Loud Thud's problem by inspection. 2^-2 = 1/(2^2) = 1/4 = 0.25

            Comment


            • #36
              Originally posted by Dave H View Post
              -2 is correct

              Sorry for suggesting log tables, my age is showing A calculator is better. The formula in 2). is not the one to use for this. You need to use loudthud's as you did to get -2 above. Formula 2). is for logs with the same base (b).
              OK.....10-4.
              So I kind of, sort of, know what I am doing. If a guy ever puts a gun to my head and says...
              "Solve this Log5, or your life."
              I will have you guys double check my answer first.
              Thanks For All.......
              https://www.youtube.com/watch?v=7zquNjKjsfw
              https://www.youtube.com/watch?v=XMl-ddFbSF0
              https://www.youtube.com/watch?v=KiE-DBtWC5I
              https://www.youtube.com/watch?v=472E...0OYTnWIkoj8Sna

              Comment

              Working...
              X