Afternoon folks,
I've just about finished up a 3-4W ecc99 amp for home recording and even at this low power it's probably still a bit too loud to crank without upsetting my neighbour, who is a lovely person so I want to avoid that. With this in mind I've been trying to understand the 0.1/1W inline attenuator found in the 1W 12AU7 based Marshall's, which I've posted a snippet of below.
The interaction with the OT taps is confusing me a little. My first thoughts is something like this and I'd appreciate a sanity check
16 ohm load
We have the 82R resistor in series with the 16R load, all in parallel with the 18R resistor to ground, thus
Rtot = 1/(1/(82+16) + 1/18) = 15.2 ohms
This looks like a sensible load for the power amp.
The 8 ohm tap doesn't do any thing here so we can ignore it.
8 ohm load
We have the 47R in series with the 8R load, all in parallel with the 18R resistor to ground on the 16 ohm tap.
This is where the interplay with the 16 ohm tap confuses me. So do I halve the value of R18, such that:
Rtot = 1/(1/(47+8) + 1/(0.5*18)) = 7.7 ohms
This looks like a sensible load for the tap. Have I missed a trick here?
Additionally, how should I calculate the dissipation in the resistors (I'm sure it's simple ohms law stuff but I'm having a brain fart today and I'm not entirely sure whats happening for the 8 ohm load...) and what is the purpose of the capacitor? It's omitted on the JTM1 for some reason.
Cheers
Ian
I've just about finished up a 3-4W ecc99 amp for home recording and even at this low power it's probably still a bit too loud to crank without upsetting my neighbour, who is a lovely person so I want to avoid that. With this in mind I've been trying to understand the 0.1/1W inline attenuator found in the 1W 12AU7 based Marshall's, which I've posted a snippet of below.
The interaction with the OT taps is confusing me a little. My first thoughts is something like this and I'd appreciate a sanity check
16 ohm load
We have the 82R resistor in series with the 16R load, all in parallel with the 18R resistor to ground, thus
Rtot = 1/(1/(82+16) + 1/18) = 15.2 ohms
This looks like a sensible load for the power amp.
The 8 ohm tap doesn't do any thing here so we can ignore it.
8 ohm load
We have the 47R in series with the 8R load, all in parallel with the 18R resistor to ground on the 16 ohm tap.
This is where the interplay with the 16 ohm tap confuses me. So do I halve the value of R18, such that:
Rtot = 1/(1/(47+8) + 1/(0.5*18)) = 7.7 ohms
This looks like a sensible load for the tap. Have I missed a trick here?
Additionally, how should I calculate the dissipation in the resistors (I'm sure it's simple ohms law stuff but I'm having a brain fart today and I'm not entirely sure whats happening for the 8 ohm load...) and what is the purpose of the capacitor? It's omitted on the JTM1 for some reason.
Cheers
Ian
Comment