I was trying to calculate the 6V6 mA draw. It seems that a 12ax7 draws 3 mA for both plates. I have the rail screen resistor of 989 ohm it drop's 3.25 volts across it and then a 9.90K ohm drops 21.5 volt then off to the 12ax7 100K plate resistors. A 383 VDC B+ .
I pulled the 12ax7 to remove it's draw and read across the 989 ohm and get a 1 volt drop 989/1= 0.001 ma . 1ma = 0.001 watt . this is at idle . Does this seem right? Or am I doing this all wrong? Isn't the 3.25 volt drop across the 989 ohm dropper 989/3.25= 0.003286 ma for the entire draw including the 12ax7? Or do I need to consider the 21.5 volt drop across the 9.90K resister?
I can't imagine I have only 1 ma draw on the 6v6 screen.
I pulled the 12ax7 to remove it's draw and read across the 989 ohm and get a 1 volt drop 989/1= 0.001 ma . 1ma = 0.001 watt . this is at idle . Does this seem right? Or am I doing this all wrong? Isn't the 3.25 volt drop across the 989 ohm dropper 989/3.25= 0.003286 ma for the entire draw including the 12ax7? Or do I need to consider the 21.5 volt drop across the 9.90K resister?
I can't imagine I have only 1 ma draw on the 6v6 screen.
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