I built a speaker break in jig with a filament transformer and a ac meter a la Ted Weber. I have always just used it on single speakers. Today a customer brought in 4 20 watt Webers to be installed in a Super Reverb, and he asked me to put them on the jig overnight. Question is, how does the math work out for the target of 1/3 power when they are all connected in parallel? Does the math use 8 ohms or 2 ohms?
"Here's the math for determining the correct voltage to use in case you have a different wattage and impedance rating than our example above:
1. Take the power rating of the speaker and divide it by 3.
2. Take that number and multiply it by the speaker's Ohm rating (4, 8, or 16)
3. Use your calculator to find the square root of that number.
4. The result is the voltage you need to use to drive the speaker at 1/3 its rated power. "
"Here's the math for determining the correct voltage to use in case you have a different wattage and impedance rating than our example above:
1. Take the power rating of the speaker and divide it by 3.
2. Take that number and multiply it by the speaker's Ohm rating (4, 8, or 16)
3. Use your calculator to find the square root of that number.
4. The result is the voltage you need to use to drive the speaker at 1/3 its rated power. "
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