I have a 50's Wurly juke box on the bench that came in among other things with its screen resistor open. It's an odd one, 69A (1650R) and 69B (9000R) are the same large wirewound heatsink mounted piece with a middle tap about two thirds to one side. The 9000R side is cracked open. I got an Ohmite 9090R 10 watt and flew it off the socket since there was no way to deal with the heatsink mount. Well, I have only had the amp on for short bits of time to service it, and the new resistor is already discoloring. I measured 331.5v across it and by my math I get 12.1 watts.
331.3 / 9090 = 0.0364 x 331.5 = 12.09 watts
So I looked at the schematic and saw that R69A is a 1650R 15 watt, and R69B is a 9000R 10 watt. How can this be if they are the same tapped resistor?
I then did the math for the print and came up with 11 watts.
315 / 9000 = 0.035 x 315 = 11 watts
SO, I don't know why the original resistor cracked open, but the currently installed one per the schematic seems to be out of it's league. Any thoughts?
Whurly schematic.pdf
BTW, For dissipation the cathode resistor measurement gives me 41.6 watts:
25.7v across 240R = 0.107A x 388.5v = 41.6w / 2 = 20.8watts per tube, which is about what I get measuring current with my socket bias tester.
331.3 / 9090 = 0.0364 x 331.5 = 12.09 watts
So I looked at the schematic and saw that R69A is a 1650R 15 watt, and R69B is a 9000R 10 watt. How can this be if they are the same tapped resistor?
I then did the math for the print and came up with 11 watts.
315 / 9000 = 0.035 x 315 = 11 watts
SO, I don't know why the original resistor cracked open, but the currently installed one per the schematic seems to be out of it's league. Any thoughts?
Whurly schematic.pdf
BTW, For dissipation the cathode resistor measurement gives me 41.6 watts:
25.7v across 240R = 0.107A x 388.5v = 41.6w / 2 = 20.8watts per tube, which is about what I get measuring current with my socket bias tester.
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