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  • Fixed AND cathode bias?

    Greetings. I have a Marshall 4001 Studio 15, which has a number of interesting features in its circuit, but one that puzzles me is the 270 ohm cathode resistors and 22 uf bypass caps on the output tubes. The schematic is linked below (but the reverse polarity of the caps as shown is incorrect). Does anyone know what is going on here?

    Martin Manning

    http://www.drtube.com/schematics/marshall/4001m88.gif

  • #2
    Bias is the voltage relation between the cathode and the grid. The tube has no idea how the bias voltage gets there, all it knows is that the grid is so much negative with respect to the cathode. usually we pick one way or the other, but nothing says you have to do it that way. You can have both methods contributing.
    Education is what you're left with after you have forgotten what you have learned.

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    • #3
      So this is a tone thing, I guess to take some of the edge off by adding a little compression? I have usually seen one or the other bias method, or switchable from one to the other, but this is the first case where I have seen both used at once.

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      • #4
        Vox used the 2 methods with the ac50
        http://www.voxamps.co.uk/downloads/circuits/ac50_1.jpg
        Individually adjustable bias for each el34 as well, and a nice self balancing paraphase inverter rather than LTP - Peter
        My band:- http://www.youtube.com/user/RedwingBand

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        • #5
          Originally posted by pdf64 View Post
          Vox used the 2 methods with the ac50
          http://www.voxamps.co.uk/downloads/circuits/ac50_1.jpg
          Individually adjustable bias for each el34 as well, and a nice self balancing paraphase inverter rather than LTP - Peter
          Interesting... thanks for pointing that one out. No bypass cap there, and a relatively small value resistor, so a different flavor.

          MPM

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          • #6
            Seen it on a Fender once as well.Had an early SF Bassman on the bench with,IIRC, a couple of 75ohms on the cathodes.Although I dont see it on any schem,it appeared to be stock.

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            • #7
              Yeah, that was one of the things people complained about with some of the SF Fenders. But I recall somebody on the old Ampage bbs experimenting with adding small cathode resistors to the power tubes of his Bassman head guinea pig amp to develope part of the bias voltage and adjusting the fixed bias supply to bring the bias voltage to what he needed to get the tubes idling properly. He liked the effect of the added compression. I think the cathode resistor was ~ 20 ohms, IIRC.

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              • #8
                Maybe some thread drift here, but I'll tack this query on:

                I just swapped the output tubes in this little amp, installing a pair of JJ 6V6S's. While doing this I had to max out the bias trimmers and still got only 21 mA out of the plates, as calculated using the OT primary resistance and voltage drop.

                Since there is a cathode resistor (here's the relevance to the original topic, I guess), there is 5.8V at the cathodes. There is -26V on the grids, and 381V on the plates. Relative to cathode voltage, the bias voltage is really -31.8, and Va is really 375. If I use these numbers to get on the published (JJ's web site) plate characteristic curves, things don't line up too well. Using Va and Vg, I should be seeing about 35 or 36 mA (not 21). Using Va and Ia, I should be at -35 or -36V Vg (not -31.8).

                From this I have to conclude that this is one cold set of tubes. They do indeed match, but they are running about 15 mA low.

                If I calculate Pa as Ia * Va, I get 0.021 * 375 = 7.9W. If Ia max is 14, then I am only running 56%. The amp doesn't sound bad, but I can't look at the output waveform right now ('scope, but no signal generator).

                Questions:

                Is my logic and math right?

                The matching numbers on the boxes is "20," and they were stuck together with a "Mojo Precision Matched" sticker. Does anyone know what unit this is?

                If I look at the published curves, the 14W Pa max line passes through 40 mA and 300V. Wouldn't that be 12W, not 14W? what's up with that?

                MPM
                Last edited by martin manning; 03-03-2008, 12:02 PM.

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                • #9
                  12 watts would be about 90% max dissipation (14 watts) which would put you in class A territory.

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                  • #10
                    Originally posted by stokes View Post
                    12 watts would be about 90% max dissipation (14 watts) which would put you in class A territory.
                    I guess I wasn't clear. There is a 14W line shown on the published curves, which passes through 40 mA and 300V. That seems to be 12W, not 14, no?

                    http://www.jj-electronic.com/pdf/6V6.pdf

                    MPM

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                    • #11
                      Originally posted by stokes View Post
                      12 watts would be about 90% max dissipation (14 watts) which would put you in class A territory.
                      ...idle dissipation wattage has no relationship to Class of operation (ie: Class-A vs. Class-AB, etc.), it's the relationship of plate idle current to peak plate current that determines whether it's Class-A (360° of conduction) or Class-AB (less-than 360° of conduction but greater-than 180° of conduction):

                      CA° = 2*ACOS[ - Ip.q / Ip.pk ]

                      where:
                      CA° = Plate conduction angle, degrees-of-conduction
                      Ip.q = Plate idle (quiescent) current (* both tubes value)
                      Ip.pk = Plate peak signal current (* single tube value)

                      ...when Ip.q and Ip.pk are EQUAL, it's 360° conduction and thus Class-A. But, whenever Ip.pk is GREATER than Ip.q, it's less-than 360° conduction and (usually) Class-AB.



                      note (*) view 'push-pull' as a single composite tube representing the two separate opposedly-operating tubes.
                      ...and the Devil said: "...yes, but it's a DRY heat!"

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                      • #12
                        Okay,ease up OTM,if you see,I used the term "class A territory" so as to avoid the whole "what constitutes class A" can of worms.Very thorough mathematical explanation,I'll give you that,but it gives me a headache just reading it.For me,taking a SE amp like a Champ,lets say,targeting 90% dissip. at idle then tweaking it for what sounds best to me,and after all,"what sounds best" is the bottom line in guitar amps,is close enough to class A.
                        Martin,yes 40ma at 300v's would be 12 watts.I dont know what you mean by "published curves",but I suspect the "chart" you are looking at is stating the tube is good for 14watts max,but the curve it is showing is a "typical operation" example?After all you wouldnt want a tube that has a 14watt max rating idling at 14 watts,at least the manufacturer wouldnt.We all know that in guitar amps we push things to the edge and over,so some of us may want to idle the tube at the max.And all the math aside,I'll stand by my statement that a 14 watt 6V6 idling at 12 watts is "class A territory",maybe not "pure class A" but close.

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                        • #13
                          Originally posted by stokes View Post
                          Okay, ease up OTM, if you see, I used the term "class A territory" so as to avoid the whole "what constitutes class A" can of worms.
                          ...sorry, I just translated "class A territory" as meaning "...never ceasing conduction..." and not as meaning "...very close to..." which is what I believe you were actually conveying.

                          ...the reason I "piped-in" is that the RCA 2 x 6L6GC 55W Class-AB circuit example has an idle dissipation percentage of 87% (58mA per tube at 450Vp) even though it's truly push-pull Class-AB, and not even close to Class-A, conduction-angle wise.

                          ...granted, 87% isn't 90%, but it's close enough to both make and illustrate the point that "high" idle wattages approaching high-90% were/are feasible with Class-AB operation; and, thus, "high idle wattage" is not a valid differentiator of whether a circuit is Class-A or Class-AB operation.
                          ...and the Devil said: "...yes, but it's a DRY heat!"

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                          • #14
                            The example you give for the 6L6GC is for class AB1,most guitar amps are AB2,no?Which,without going into the numbers,you have the manual, is about 70%max plate diss. as a general rule.And we could go back and forth for days.Look,I'll admit your explanation is probably a spot on,lab definition,for class A.But in guitar amps we tend to break a lot of rules and push tubes beyond their limits,but going by the manuals,and using guitar amps as the subject,AB2 would be described as about 70% max diss and class A is about 90%.I am not saying your definition is wrong by any stretch,and that for a technical definition there arent other parameters to be considered,but for guitar amps,the 70% class AB2 and the 90% class A as a general rule of thumb are close enough,in my experience anyway.

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                            • #15
                              ...two points: (1) Leo Fenders original amps were biased and operated from the factory as basically Class-AB1 for "clean" sounds, hence the "cold" idle bias and typically "deep" negative fixed-bias voltages (ie: -51/-52Vdc, etc.)...but, (2) most people (especially today) don't leave their amps biased cold as they come from the factory, nor do the play them cleanly.

                              ...when people cranked up Leo's factory bias, which was about 55% for 6L6s and 60% for 6V6s, and pushed ever greater guitar signals into the jacks, the result was indeed that most "original" -AB1 amps got pushed/played in "hot" -AB2 conditions...ie: the control grids went positive and began conducting, the very definition between suffix "-1" (never goes postive) and suffix "-2" (goes postive at some time).

                              ...oh, what about that "deep" negative fixed-bias voltage (ie: -51/-52Vdc, etc.)? Well, it was there for a reason, because when the "numbers" are backsolved, a 40W output would only require a 35V.rms input drive signal amplitude, representing a 50V.pk (sinusoidal) value, which was about 1-2Vdc below the bias voltage...for Class-AB1 operation.

                              ...as you said: it's all there in the tube manuals.
                              Last edited by Old Tele man; 03-04-2008, 04:43 AM.
                              ...and the Devil said: "...yes, but it's a DRY heat!"

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