Hi everyone, sorry in advance if this question doesn't make sense, I'm pretty new to digging around amps. But I love it!
I have a question about soon-to-be-in-my-possession Ampeg Gemini VI amplifier. It has a 7199 tube used as its phase inverter, and since that tube has a pentode + a triode in it, I'm kind of wondering how that works.
The source of my confusion is the following: I have heard that for your normal 12AX7-type dual triode phase inverter, you want to use a tube that is well balanced, with the two halves of the tube as close as possible. Since the two halves of the 7199 are so different, how does that work? Looking at the schematic, it looks like part of the pentode does the PI work, then the triode does it's thing..... ?
Here is the schematic: http://members.aol.com/portaflex/schems/gs-15-r.gif
I have a question about soon-to-be-in-my-possession Ampeg Gemini VI amplifier. It has a 7199 tube used as its phase inverter, and since that tube has a pentode + a triode in it, I'm kind of wondering how that works.
The source of my confusion is the following: I have heard that for your normal 12AX7-type dual triode phase inverter, you want to use a tube that is well balanced, with the two halves of the tube as close as possible. Since the two halves of the 7199 are so different, how does that work? Looking at the schematic, it looks like part of the pentode does the PI work, then the triode does it's thing..... ?
Here is the schematic: http://members.aol.com/portaflex/schems/gs-15-r.gif
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