Power in an electronic device is always voltage across it times the current through it. If these are not DC or almost so, you have to take into account the instantaneous values and integrate to get the power. But you're worried about DC.
To wipe off X volts from a voltage of B volts, you need an X volt zener. Or any two zeners which add to X. The power dissipated in the zener is the voltage across it (X) times the current through it, which is the max current drawn from the power supply. Let's say that the current drawn is Y.
So the power needed is X*Y in watts if X is volts and Y is amperes. Example: Dropping 20V from a 500V power supply which supplies 350 ma. You need a 20V zener which can dissipate 20 * 0.35 = 7W. For safety, I would not put less than a 10W zener in there.
You could use two 10V/5W zeners in series. Each drops ten of the 20V and each dissipated 10*0.35 = 3.5W of heat.
If you want to drop 50V off, you need a 50V zener that can dissipate 50*0.35 = 17.5W, and I would use a 20W zener. However, you could also use five 10V/5W zeners. Or three 16V 10W zeners.
The total zener voltage must add up to the voltage you want dropped, and the total zener power must add up to the actual voltage times current to be dissipated plus some safety factor. If you do not allow for getting the heat out of the parts, they will burn up.
You cannot successfully parallel zeners and have them share the load equally with simple circuits. Restrict yourself to simple series connections for more voltage.
You can use a low power zener plus a high power MOSFET or bipolar transistor to make an "amplified zener". In this case the zener sets the voltage to be dropped, and the transistor carries all the power. However, it is easier to get high power transistors and MOSFETs than high power zeners. A 1/2W zener, a resistor, and a power MOSFET can make a 25-50W zener as long as you can get the heat out of the MOSFET.
Remember in any of these that the device dropping the power may or may not be able to be tied to the chassis because of the voltage on it.
To wipe off X volts from a voltage of B volts, you need an X volt zener. Or any two zeners which add to X. The power dissipated in the zener is the voltage across it (X) times the current through it, which is the max current drawn from the power supply. Let's say that the current drawn is Y.
So the power needed is X*Y in watts if X is volts and Y is amperes. Example: Dropping 20V from a 500V power supply which supplies 350 ma. You need a 20V zener which can dissipate 20 * 0.35 = 7W. For safety, I would not put less than a 10W zener in there.
You could use two 10V/5W zeners in series. Each drops ten of the 20V and each dissipated 10*0.35 = 3.5W of heat.
If you want to drop 50V off, you need a 50V zener that can dissipate 50*0.35 = 17.5W, and I would use a 20W zener. However, you could also use five 10V/5W zeners. Or three 16V 10W zeners.
The total zener voltage must add up to the voltage you want dropped, and the total zener power must add up to the actual voltage times current to be dissipated plus some safety factor. If you do not allow for getting the heat out of the parts, they will burn up.
You cannot successfully parallel zeners and have them share the load equally with simple circuits. Restrict yourself to simple series connections for more voltage.
You can use a low power zener plus a high power MOSFET or bipolar transistor to make an "amplified zener". In this case the zener sets the voltage to be dropped, and the transistor carries all the power. However, it is easier to get high power transistors and MOSFETs than high power zeners. A 1/2W zener, a resistor, and a power MOSFET can make a 25-50W zener as long as you can get the heat out of the MOSFET.
Remember in any of these that the device dropping the power may or may not be able to be tied to the chassis because of the voltage on it.
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