Well I got this amp where the plate voltage is 509V and the bias supply voltage is 59v. Luckily despite the two 6L6GC tubes being different brands they match up nearly perfect right about 20ma a tube. The cabinet says this is a 6G6-B where the printed B+ is 428v and my circuit matches the 6G6-B. I guess I am a bit surprised to see 509v plate voltage and I would be less surprised if it was the 6G6-A model where the printed B+ was 470v. Not a worry though since I installed 600v filter caps.
So I am wanting to get the bias supply closer to 55v or so. At this point I would just parallel another resistor onto the 27K bias resistor (shunt resistor right?). I know enough that 100k-150k resistor paralleled to the 27k would bring the total resistance to around 21-22k. Can anyone help me understand how to perform the math to be able to accurately approximate what the bias supply voltage would be after altering the 27k resistor to a lower value? Thanks for any help and guidance. Also do I have this correct that lowering the 27k resistor will indeed bleed some more voltage to ground in return lowering overall bias supply voltage?
So I am wanting to get the bias supply closer to 55v or so. At this point I would just parallel another resistor onto the 27K bias resistor (shunt resistor right?). I know enough that 100k-150k resistor paralleled to the 27k would bring the total resistance to around 21-22k. Can anyone help me understand how to perform the math to be able to accurately approximate what the bias supply voltage would be after altering the 27k resistor to a lower value? Thanks for any help and guidance. Also do I have this correct that lowering the 27k resistor will indeed bleed some more voltage to ground in return lowering overall bias supply voltage?
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