Originally posted by Wrongdog
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In series (NOT recommended, and usually provides no benefit) the voltage divides up in inverse proportion to the values of the caps. So, if you put a 10 uF and a 100 uF in series and apply 550VDC, the 10 uF cap will drop 500V and the 100 uF cap will drop 50V. That is assuming the individual voltage ratings of the caps will allow this without frying them.
The total Capacitance of that series pair can be found by using the product over sum: (100 uF x 10 uF)/(100 uF + 10 uF) = 9.09 uF
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