If I have uncharged alnico pole pieces and I just stick neo disc magnets to the bottom to provide the magnetism, what will it sound like?
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Originally posted by cnb77 View PostIf I have uncharged alnico pole pieces and I just stick neo disc magnets to the bottom to provide the magnetism, what will it sound like?
DiMarzio does something similar with the Ultra Jazz bass pickups. They use alnico poles charged with ceramic magnets.
Give it a try and see what you get.It would be possible to describe everything scientifically, but it would make no sense; it would be without meaning, as if you described a Beethoven symphony as a variation of wave pressure. — Albert Einstein
http://coneyislandguitars.com
www.soundcloud.com/davidravenmoon
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Whatever metal used in the poles (core) will have a limit to the amount of power it can accept before it becomes saturated. Unless you use very thin Nd magnets that don't exceed the capacity of the AlNiCo, that will likely happen. It will decrease inductance and maybe cause phase cancellations from eddy currents. Not sure about that last affect.
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Don't know what saturates sooner, but the AlNiCo should become permanently magnetized. There is no point in keeping the Nd magnets on them. Even the lowest Gauss 1/32" thick N35 magnet's have much higher Guass than is recommended for a pickup, and will cause string modulation unless some measures are taken to reduce the power above the pickup surface. You could use some kind of spacers, but there are other methods I don't know about.
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Add Nd magnets to *all* the Alnico rods, otherwise the Nd magnets might partially demagnetize the adjacent Alnico rods because of their much lower coercivity."Det var helt Texas" is written Nowegian meaning "that's totally Texas." When spoken, it means "that's crazy."
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Originally posted by Fluoroscope 5000 View PostDon't know what saturates sooner, but the AlNiCo should become permanently magnetized. There is no point in keeping the Nd magnets on them. Even the lowest Gauss 1/32" thick N35 magnet's have much higher Guass than is recommended for a pickup, and will cause string modulation unless some measures are taken to reduce the power above the pickup surface. You could use some kind of spacers, but there are other methods I don't know about.It would be possible to describe everything scientifically, but it would make no sense; it would be without meaning, as if you described a Beethoven symphony as a variation of wave pressure. — Albert Einstein
http://coneyislandguitars.com
www.soundcloud.com/davidravenmoon
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Originally posted by Fluoroscope 5000 View PostDon't know what saturates sooner, but the AlNiCo should become permanently magnetized. There is no point in keeping the Nd magnets on them. Even the lowest Gauss 1/32" thick N35 magnet's have much higher Guass than is recommended for a pickup, and will cause string modulation unless some measures are taken to reduce the power above the pickup surface. You could use some kind of spacers, but there are other methods I don't know about.
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Even 1/32" thick Nd35 can have 2x+ the Gauss that a 0.71" AlNiCo V rod can hold. I don't know how much it takes to magnetize such a rod, but it's likely to be enough to do something. It is a fact that saturating the core will decrease inductance, as David's 300G reading on the steel blades may be an indication of. You might actually get higher Gauss from the blades if you used lower Gauss magnets that don't exceed the (permeability?) of the blades. I'm not sure how all that works, but I know it is an issue. Furthermore, I would think the field might form ripples around the core from too much power being forced through the material. Speculation on my part, but makes sense. If true, those ripples (eddy currents) will cause some types of phase cancellations.
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Originally posted by Fluoroscope 5000 View PostEven 1/32" thick Nd35 can have 2x+ the Gauss that a 0.71" AlNiCo V rod can hold.
Originally posted by Fluoroscope 5000 View PostI don't know how much it takes to magnetize such a rod, but it's likely to be enough to do something.
Originally posted by Fluoroscope 5000 View PostIt is a fact that saturating the core will decrease inductance, as David's 300G reading on the steel blades may be an indication of. You might actually get higher Gauss from the blades if you used lower Gauss magnets that don't exceed the (permeability?) of the blades. I'm not sure how all that works, but I know it is an issue.
Originally posted by Fluoroscope 5000 View PostFurthermore, I would think the field might form ripples around the core from too much power being forced through the material. Speculation on my part, but makes sense. If true, those ripples (eddy currents) will cause some types of phase cancellations.
Atomic current loops are small magnetic dipoles, usually grouped together in domains with all of them pointing in the same direction. The external field causes domains to flip, lining more of them up. Domains in a high permeability material are easier to flip than in a low permeability material. A permanent magnet is a material in which the domains remain flipped when the applied field is removed. Very strong magnets (such as Neo) have low permeability since nearly all the domains are already lined up and it is quite difficult to flip more.
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Originally posted by Mike Sulzer View PostBut if you saturate the steel blade, you have the maximum magnetization it can support, and so you get the highest reading above it. Using weaker magnets will not give a stronger field at the top of the blade.
Alnico:
Humbucker size A5
Magnet = 452G
At blade = 224G
Ceramic 8:
3.33"L x .196"W x .500"T
Magnet = 1271G
At Blade = 502G
N42 Neodymium:
1"L x .500"W x .250"T
Magnet = out of range (>1500)
At blade = 704G
The blades were 3"L x .125W X .750"T and made from 1010 carbon steel. I put one on each side of the magnet and read the north pole on each one.
Is the blade with the neo saturated? I wonder if the reading would be higher otherwise?It would be possible to describe everything scientifically, but it would make no sense; it would be without meaning, as if you described a Beethoven symphony as a variation of wave pressure. — Albert Einstein
http://coneyislandguitars.com
www.soundcloud.com/davidravenmoon
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Originally posted by David Schwab View PostIs the blade with the neo saturated? I wonder if the reading would be higher otherwise?
Notice that the ratio, Bmagnet to Bblade is not quite the same for the alnico and ceramic. This might mean that even with the ceramic, the steel right at the magnet could be saturated, or at least on a portion of the B-H curve with decreasing slope if not completely saturated.
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What's missing is the difference between field intensity (in Gauss or Tesla) and total flux (in Webers). The Neos (like all permanent magnets) generate total flux in proportion to their volume. This flux then spreads out through the iron and air, and the field intensity is set by the flux per unit area of the iron poles. (Well, I'm simplifying, as the iron can saturate and not all the neo flux will go through the iron, et cet, but this rule is pretty good.)
Weber (unit) - Wikipedia, the free encyclopedia
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