Mozwell-thanks for your efforts and I will see if there is some
common features that will help me.
I am still interested in getting the matching schematic if at all available
The one thats in the one on my bench is from a fender twin. I know THATS wrong.
I wouldn't be so sure. That's a fairly hefty power amp driving the tank (J77 & K214 & a bunch of 5W resistors).
Why not utilize the most common tank in the world?
Originally posted by Enzo
I have a sign in my shop that says, "Never think up reasons not to check something."
I wouldn't be so sure. That's a fairly hefty power amp driving the tank (J77 & K214 & a bunch of 5W resistors).
Why not utilize the most common tank in the world?
I'm trying to analyze this schematic and I just don't understand the input board. I don't know if anybody can help me.
Guitar jack has as far as I know only Tip and Sleeve (TS), at least mine. But this input has Tip, Ring, Sleeve. And if I understand the Jack symbol correctly, the Ring goes to the voltage follower input stage. But the Ring will be the GND (Sleeve) of the Guitar, ...
And the Tip of this input board or jack will be grounded by the amp...
And if I understand the Jack symbol correctly, the Ring goes to the voltage follower input stage. But the Ring will be the GND (Sleeve) of the Guitar, ...
And the Tip of this input board or jack will be grounded by the amp...
Any idea what I misunderstand?
They have just drawn the symbol wrong. Tip and ring are reversed. If you look at the 'Send' jack, it is drawn as if there is no tip at all, just ring and sleeve.
Originally posted by Enzo
I have a sign in my shop that says, "Never think up reasons not to check something."
Oh, thank you very much. Good point to check the other jacks. The 'receive' jack is as well a bit challenging to understand :-).
I really dare to ask another question about this schematic, but if someone still like to solve a schematic challenge:
How can this "Clean Green" ever light up? :
And on this same schematic screen shot.You see a kind of integrator amp (Used to switch channel, therefore CH input on the left). But at the opamp positiv terminal you always have the diode forward voltage (~570mV if using a 1N4148) and on the negative terminal you will always have B- plus forward voltage. Independent of CH input (which is 0V or twice diode forward voltage).
The output of the amp will always be negative rail.
Comment