SF Twin Reverb no sound

[JAelec]

If I'd like to lower the bias of this amp from the 68% PD in its current state, then I would replace the 15k (actually 14k) resistor (the one attached to the bias balance pot) with perhaps a 20k or a 24k one.

If I want to calculate the wattage required for this resistor, would this be the correct way to do it?

I measured the voltage drop across the 14k resistor to 49.4V
So the current should be 49.4 V / 1400 Ohms = 0.035 A
The power dissipation across that resistor should then be 0.035 x 49.4 = 1.729 W

So would I be correct in that I would need a 3W resistor?

[Helmholtz]

I measured the voltage drop across the 14k resistor to 49.4V
So the current should be 49.4 V / 1400 Ohms = 0.035 A
The power dissipation across that resistor should then be 0.035 x 49.4 = 1.729 W

14k = 14000R. You used 1400 = 1.4k for calculation.
Power is V²/R, so roughly 0.17W.

[JAelec]

14k = 14000R. You used 1400 = 1.4k for calculation.
Power is V²/R, so roughly 0.17W.

Right you are... thanks! And the P=V²/R is faster to use, good point.