MEF members….
Ok, I am pushing myself to learn some tube and Output Transformer theory today. And if this has been answered in another thread, my apologies. I did find two threads but not sure that either answers my question.
Output transformer observation/question/thought process
output transformer impedence matching
I was watching a video (Uncle Doug - Impedance Ratio: The Easiest Way to Decipher Output Transformers) on Output transformers and calculating Impedance ratios and matching to tubes. The idea is that you have an OT, not sure of specs, etc, and then try to figure out how to use it in an amp. In the video, the scenario seems to be you have the OT and two output tubes, in Class AB, push pull. In the case of the Uncle Doug video (at around the 25 minutes point), he shows you how to (1) calculate the Impedance ratio of the OT, (2) review the spec sheet of a 6L6 tube, look for Class AB, 360v, and there we see 3,800 ohms for the load resistance, and (3) determine the load that can be applied to the OT secondary leads.
In Doug’s video, we have the following (at the 25 minute point).
OT Impedance Ratio = 1003 (measured or calculated)
Tube Load Resistance = 3,800 (spec sheet, at 360 volts, see below)
OT speaker impedance across windings = (Tube Load Resistance) / (OT Impedance Ratio)
OT speaker impedance across windings = (3800) / (1003) = 3.78 ohms for the Yellow and White leads of the secondary.
Ok, I get all that. BUT… what happens if your amp has FOUR output tubes. Do you still use the 3,800 spec or do you change that in the calculation.
Thanks in advance.
Spec Sheet - 6l6g.pdf
Ok, I am pushing myself to learn some tube and Output Transformer theory today. And if this has been answered in another thread, my apologies. I did find two threads but not sure that either answers my question.
Output transformer observation/question/thought process
output transformer impedence matching
I was watching a video (Uncle Doug - Impedance Ratio: The Easiest Way to Decipher Output Transformers) on Output transformers and calculating Impedance ratios and matching to tubes. The idea is that you have an OT, not sure of specs, etc, and then try to figure out how to use it in an amp. In the video, the scenario seems to be you have the OT and two output tubes, in Class AB, push pull. In the case of the Uncle Doug video (at around the 25 minutes point), he shows you how to (1) calculate the Impedance ratio of the OT, (2) review the spec sheet of a 6L6 tube, look for Class AB, 360v, and there we see 3,800 ohms for the load resistance, and (3) determine the load that can be applied to the OT secondary leads.
In Doug’s video, we have the following (at the 25 minute point).
OT Impedance Ratio = 1003 (measured or calculated)
Tube Load Resistance = 3,800 (spec sheet, at 360 volts, see below)
OT speaker impedance across windings = (Tube Load Resistance) / (OT Impedance Ratio)
OT speaker impedance across windings = (3800) / (1003) = 3.78 ohms for the Yellow and White leads of the secondary.
Ok, I get all that. BUT… what happens if your amp has FOUR output tubes. Do you still use the 3,800 spec or do you change that in the calculation.
Thanks in advance.
Spec Sheet - 6l6g.pdf
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